2(x^2+8)=3(x^2+4)+1

Solution for 2(x^2+8)=3(x^2+4)+1 equation:

Simplifying
2(x2 + 8) = 3(x2 + 4) + 1

Reorder the terms:
2(8 + x2) = 3(x2 + 4) + 1
(8 * 2 + x2 * 2) = 3(x2 + 4) + 1
(16 + 2x2) = 3(x2 + 4) + 1

Reorder the terms:
16 + 2x2 = 3(4 + x2) + 1
16 + 2x2 = (4 * 3 + x2 * 3) + 1
16 + 2x2 = (12 + 3x2) + 1

Reorder the terms:
16 + 2x2 = 12 + 1 + 3x2

Combine like terms: 12 + 1 = 13
16 + 2x2 = 13 + 3x2

Solving
16 + 2x2 = 13 + 3x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x2' to each side of the equation.
16 + 2x2 + -3x2 = 13 + 3x2 + -3x2

Combine like terms: 2x2 + -3x2 = -1x2
16 + -1x2 = 13 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
16 + -1x2 = 13 + 0
16 + -1x2 = 13

Add '-16' to each side of the equation.
16 + -16 + -1x2 = 13 + -16

Combine like terms: 16 + -16 = 0
0 + -1x2 = 13 + -16
-1x2 = 13 + -16

Combine like terms: 13 + -16 = -3
-1x2 = -3

Divide each side by '-1'.
x2 = 3

Simplifying
x2 = 3

Take the square root of each side:
x = {-1.732050808, 1.732050808}